Programming Exercise #4: Super fun edition

[Programmer]

Originally Posted by Tolnaftate2004

This does not test if switching 2 people forms compatibility...

Picky, Picky.

PHP Code:

function onCreated()
{
  this.start = timevar2;
  
  this.incompatability = {
    {102, 284},
    {392, 126},
    {1, 2},
    {3, 4},
    {5, 6},
    {7, 8}
  };
  
  
  this.studentsSelected.clear();
  this.studentGroups.clear();
  
  numStudentsSelected = 0;
  // Select students at random
  for (i = 0; i < 100; i++)
  {
    f = int(random(0, 400));
    
    if (this.studentsSelected.index(f) == -1)
    {
      this.studentsSelected.add(f);
    } else
    {
      i--; continue;
    }
  }
  
  // Group them
  for (i = 0; i < this.studentsSelected.size(); i += 2)
  {
    this.studentGroups.add({this.studentsSelected[i], this.studentsSelected[i+1]});
  }
  
  // Remove incompatabilities
  for (i = 0; i < 50; i++)
  {
    sGroup = this.studentGroups[i];
    
    for (a = 0; a < this.incompatability.size(); a++)
    {
      if ((sGroup[0] == this.incompatability[a][0] || sGroup[0] == this.incompatability[a][1]) && (sGroup[1] == this.incompatability[a][0] || sGroup[1] == this.incompatability[a][1]))
      {
        echo("INCOMPATABILITY: " @ sGroup);
        
        // we've found an incompatability, so lets flip this student with the next group
        sGroup2 = this.studentGroups[i+1];
        
        sGroup[0] = sGroup2[0];
        
        this.studentGroups[i] = sGroup;
        this.studentGroups[i+1] = sGroup2;
        
        i--;
        continue;
      }
    }
  }
  
  this.end = timevar2;
  
  echo(this.end - this.start);
  
  for (i = 0; i < 50; i++)
  {
    echo("Group " @ (i+1) @ ": {" @ this.studentGroups[i][0] @ ", " @ this.studentGroups[i][1] @ "}");
  }
} 


Time: 0.001927852