Programming Exercise #2

[Chompy]

PHP Code:


/* Loops through a given wordlist
    
    First checks if the current word in the wordlist
    contains the letters the checking word does

    then checks the length of the current
    word and the checking word
*/
function findanagram(word) {
  temp.wordlist = getwordlist();
  temp.matches = "";
  for(temp.currentword : wordlist) {
    temp.y = "";
    temp.cword = uppercase(currentword);
    temp.word2 = uppercase(word);
    // Checking 
    for(temp.i = 0; i < cword.length(); i++) {
      if (word2.pos(cword.charat(i)) > -1) y @= "y";
      else y @= "n";
    }
    if (y.pos("n") == -1) { // Checking purposes
      temp.locw = cword.trim().length(); // length of currentword (for loop)
      temp.low = word2.trim().length(); // length of word (params)
      if (locw == low) {// if length of both comparing words are the same
        if (currentword != word) matches @= currentword @", ";
      }
    }
  }
  if (matches.length() > 0) { 
    return matches;
  }
}
// Edit this to return the wordlist used
function getwordlist() {
  temp.list.loadlines("temp/wordlist.txt");
  return list;
} 


And you need to set maxlooplimit if your wordlist count is higher then the loop limit :o

Edit getwordlist() at the bottom to return the wordlist used. I used a wordlist which I uploaded to temp (if anyone wants to try with that I can rar it and attach, but you might need to edit it (graal doesn't like to loop through 317k words )) :O

And.. don't hurt me if this isn't a good anagram finder