[Tolnaftate2004]

Originally Posted by Kristi

yes but you also have to find which arrangements are actually words in the dictionary.... fun fun fun

Are we given said dictionary?

edit:

NPC Code:

---

function arrange(letters,first) {

  temp.len = letters.length();

  if (first == 0) first = "";

  if (temp.len > 1) {

    temp.returns.clear();

    temp.htable = {0,0,0,0,0,0,0,0,0,0,0,0,0,

                  0,0,0,0,0,0,0,0,0,0,0,0,0,1};

    for (temp.i=0; temp.i<temp.len; temp.i++) {

      temp.letter = letters.charat(temp.i).tolower();

      temp.hindex = (max(96,min(123,getascii(temp.letter)))-97)%27; // maps characters outside of a-z to htable[26]

      if (temp.htable[temp.hindex] == 0) {

        temp.htable[temp.hindex] = 1;

        temp.pref= first @ temp.letter;

        temp.endings = arrange(letters.substring(0,temp.i) @ letters.substring(temp.i+1),temp.pref);

        temp.returns.addarray(temp.endings);

      }

    }

    return temp.returns;

  }

  else {

    temp.word = first @ letters.tolower();

    if (inDictionary(temp.word))

      return {temp.word};

    else return char(0);

  }

}

---

Now I just need some inDictionary(word).