Ive been trying to work with GUI's but I can't get them to update in a timeout.
PHP Code:
function onTimeout(){
for(temp.i=0;temp.i<player.hearts; temp.i++){
new GUIShowImgControl("PhilSmith_Hearts_"@i){
//set the hearts and stuff
}
}
setTimer(.05);
}
Would this work? Is it possible, given the correct values, that the script would just "delete"(not show) an image? Just wondering if you can edit a GUIShowImg() by setting new values to the same name.