Graal Forums - Box Checks

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Switch

04-11-2010 10:23 AM

Box Checks

1 Attachment(s)

Is there any way to check if a number that is between a set of two numbers is inside of a point between two numbers? Mostly for checking if any point of a player's body is inside of an area, similar to findareanpcs().
I think my picture will explain it better than i could in words.
Note that there's no definite location of where the number(s) could be (as it could be hit in various spaces), so I can't check for only one point/general location.

cbk1994

04-11-2010 10:38 AM

1 Attachment(s)

Just use a point to tell if it's inside. Alternatively, use radiuses.

Switch

04-11-2010 10:51 PM

Quote:

Originally Posted by Switch (Post 1568455)

Note that there's no definite location of where the number(s) could be (as it could be hit in various spaces), so I can't check for only one point/general location.

Quote:

Originally Posted by cbk1994 (Post 1568458)

Just use a point to tell if it's inside. Alternatively, use radiuses.

And I can't use radii because that can cut off corners.

fowlplay4

04-11-2010 10:58 PM

You want to do this..?

PHP Code:


		
			
if (player.x in |this.x - 6, this.x + 6| && player.y in |this.y - 6, this.y + 6|) {

  // In Box

}

Use that and you could..

1. Check the center
2. Check the corners

Switch

04-11-2010 11:09 PM

Quote:

Originally Posted by fowlplay4 (Post 1568558)

You want to do this..?

PHP Code:


		
			
if (player.x in |this.x - 6, this.x + 6| && player.y in |this.y - 6, this.y + 6|) {

  // In Box

}

Use that and you could..

1. Check the center
2. Check the corners

Can't really because it's a largish area.

More along the lines of this (though not possible)

PHP Code:


		
			
if (|player.x, player.x+3| in |this.x, this.x+this.movementx| && |player.y, player.y+3| in |this.y, this.y+this.movementy|) {

  //overlapping points

}

fowlplay4

04-11-2010 11:18 PM

Then use a for loop?

PHP Code:


		
			
for (temp.i = player.x; temp.i < (player.x + 3); temp.i++) {

  for (temp.j = player.y; temp.j < (player.y + 3); temp.j++) {

    if (temp.i in |this.x - 6, this.x + 6| && temp.j in |this.y - 6, this.y + 6|) { 

      // In Box 

    } 

  }

}

Switch

04-11-2010 11:26 PM

Quote:

Originally Posted by fowlplay4 (Post 1568565)

Then use a for loop?

PHP Code:


		
			
for (temp.i = player.x; temp.i < (player.x + 3); temp.i++) {

  for (temp.j = player.y; temp.j < (player.y + 3); temp.j++) {

    if (temp.i in |this.x - 6, this.x + 6| && temp.j in |this.y - 6, this.y + 6|) { 

      // In Box 

    } 

  }

}

I was seeing if there was a way to do it without loops.

WhiteDragon

04-11-2010 11:35 PM

Check out the separating axis theorem.

Switch

04-12-2010 10:44 PM

Quote:

Originally Posted by WhiteDragon (Post 1568572)

Check out the separating axis theorem.

Although not as simple as this, it gave me a good idea on how to go about this, and works perfect! Thanks for the springboard. :)
Checked if either of the image's edges are inside another one, so there are 4 checks each for horizontal and vertical.

Switch

05-16-2010 11:13 PM

Forgot to post this, but if anyone is wondering what I've done for this, I've posted it below.

PHP Code:


		
			
function checkCollision(firstx, firsty, firstw, firsth, secondx, secondy, secondw, secondh) {
  if ((firstx <= secondx && firstx+firstw >= secondx+secondw) || (firstx >= secondx && firstx+firstw <= secondx+secondw) || (firstx <= secondx && firstx+firstw >= secondx) || (firstx <= secondx+secondw && firstx+firstw >= secondx+secondw)) {
    if ((firsty <= secondy && firsty+firsth >= secondy+secondh) || (firsty >= secondy && firsty+firsth <= secondy+secondh) || (firsty <= secondy && firsty+firsth >= secondy) || (firsty <= secondy+secondh && firsty+firsth >= secondy+secondh)) {
      return true;
    }
  }
}

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