Quote:
Originally Posted by Tricxta
Anyhow if it's not and I mis-interpreted the question and the length of a car is 2 units as well as the width... then I'd:
1)Find the original radius:
100=2*pi*r
100/2/pi=r
r=15.9(rounded)
2)then subtract 2 units(length of the car) from that
r=13.9
3)Find the new circumfrence
circ=2*pi*13.9
circ=87.3(rounded)
The amount of cars able to fit in the parking lot is now:
=86/2
=43
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1. The width of a car has nothing to do with the problem.
2. The cars are parallel parking
AROUND a circle.
3. Nope.