Quote:
Originally Posted by Googi
No it wouldn't. Suppose that there's a machine where I have a 50% chance of losing whatever I put in and a 50% chance of receiving twice the value of the plat I put in in tokens (such a machine would statistically break even). For the sake of simplicity, we'll assume that if I put in 500 plat and win, I get 1000 tokens (if I put in 500 and lose, I obviously get zero.) Playing the machine 20 times would result in an average payout of 10000 tokens (I should win 1000 tokens about ten times and win nothing about ten times). If 10000 tokens = 1 EC (which it would have to if we're operating from the premise that 10000 plat = 20 diamonds = 1 EC is the "ideal" EC value) then the average time that I put 10000 plat into the machine I get 1 EC. I am doing what amounts to a currency conversion.
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Yes, but you have to assume that some people will win more and some will lose more, and as you know in all casinos, the house always wins. Make it more like 33% win 66% lose.